The complete factorization of 15x² - 6x + 5xy - 2y is (5x - 2)(3x + y)Step-by-step explanation:If we have an expression of four terms, then we factorize it by usingthe grouping factorizationIn grouping factorization we do that1. Collect each two terms with common factors into 2 brackets 2. Take the common factor from each bracket, which make the brackets equal each other3. Take the bracket as a common factor, the answer will be 2 factors multiply by each other∵ The expression is 15x² - 6x + 5xy - 2y- Take the first 2 terms in a bracket and the last 2 terms in another bracket∴ (15x² - 6x) + (5xy - 2y)∵ The common factor of 15x² and 6x is 3x- Divide each term by 3x∵ 15x² ÷ 3x = 5x∵ 6x ÷ 3x = 2∴ (15x² - 6x) = 3x(5x - 2)∵ The common factor of 5xy and 2y is y- Divide each term by the common factor y∵ 5xy ÷ y = 5x∴ 2y ÷ y = 2∴ (5xy - 2y) = y(5x - 2)∴ (15x² - 6x) + (5xy - 2y) = 3x(5x - 2) + y(5x - 2)∵ The bracket (5x - 2) is a common factor of the two terms- Divide each term by the common factor (5x - 2)∵ 3x(5x - 2) ÷ (5x - 2) = 3x∵ y(5x - 2) ÷ (5x - 2) = y∴ 3x(5x - 2) + y(5x - 2) = (5x - 2)(3x + y)∴ 15x² - 6x + 5xy - 2y = (5x - 2)(3x + y)The complete factorization of 15x² - 6x + 5xy - 2y is (5x - 2)(3x + y)Learn more:You can learn more about the factors in brainly.com/question/10771256 #LearnwithBrainly